Question: I. Solve for x. 42-3 . 8 - 13 2. Evaluate the following logarithm (a) log . 98 - los ; 7 (b) log 200

 I. Solve for x. 42-3 . 8 - 13 2. Evaluatethe following logarithm (a) log . 98 - los ; 7 (b)log 200 - log 2 (c) log1050 - log 105(d) logo 25- logo75 (e) 251085 + Blogs V5 Of log Vio (g) log25 + log 4 (1) 2 549 () 1000 loss\f5. Solve forx and check for any extraneous roots (a) logxx +logs(x + 2)- 1 (b) log (x+3) - log(2x-1) - -16. A sum of$20,000 is invested in an account at a nominal rate of 6%annually. How much is in the account after 5 years if theinterest is compounded a) annually (b) quarterly (c) monthly (d) continuously A= PelAn amount of $10,000 is deposited into an account that earns4 % interest compounded quarterly. Let A(t) represent the balance (in thousandsof dollars) in the account after t years or any fraction thereof.(a) Find a formula for A(t) (b) Find the balance after 10years. (c) What is the doubling-time? (a) A(!) = 10000 1 0.04(b) (c) 10000 1 - 0.04 4 - 20000 (1.01)" -2 log(1.01)" = log 2A particle decays at a rate of 0.45% annually.Assume and initial amount of 300 (a) How much of the particle
remains after 60 years? (b) What is the half-life of the particle?(a) 4=300e-0.0045 A = 300e-0.064360) A = 300 e-0 0045 60) A=300e-0.271 = 229 mg 300 2 0045 = 150 = 0.5 Ine-0.0045 = In 0.5A colony of bacteria grows according to the lawN = Noe". At the start of a certain experiment there was144 bacteria present. Eight hours later it was observed that the colonyhas grown to 720. What was the size of the population 6hours after the start of the experiment? When 1 =0 N =144ek When t - 8 720 - 144ek(8) 720 = 14484 5- git In5 - Ine In5 - 8k k = = =0.2012 8 When t - 6 N - 48110. The half-life ofa certain radioactive substance is 16 days. An initial amount of 30grams is obtained for a medical treatment. What is the amount ofthe substance after 9 days? [Use N = Noel] N = 30ekWhen t = 16 30ek(16)- 15 N = 30g-0.043321 61 1. Evaluatethe following logarithm without the use of a calculator. (a) log 10(b) Inve (c) 1000 loss (d) e 2last 12. Use the propertiesof logarithm to express as sum or difference Ve (a) In (b)

I. Solve for x. 42-3 . 8 - 13 2. Evaluate the following logarithm (a) log . 98 - los ; 7 (b) log 200 - log 2 (c) log1050 - log 105(d) logo 25 - logo75 (e) 251085 + Blogs V5 Of log Vio (g) log 25 + log 4 (1) 2 549 () 1000 loss\f5. Solve for x and check for any extraneous roots (a) logxx +logs(x + 2) - 1 (b) log (x+3) - log(2x-1) - -16. A sum of $20,000 is invested in an account at a nominal rate of 6% annually. How much is in the account after 5 years if the interest is compounded a) annually (b) quarterly (c) monthly (d) continuously A = PelAn amount of $10,000 is deposited into an account that earns 4 % interest compounded quarterly. Let A(t) represent the balance (in thousands of dollars) in the account after t years or any fraction thereof. (a) Find a formula for A(t) (b) Find the balance after 10 years. (c) What is the doubling-time? (a) A(!) = 10000 1 0.04 (b) (c) 10000 1 - 0.04 4 - 20000 (1.01)" -2 log (1.01)" = log 2A particle decays at a rate of 0.45% annually. Assume and initial amount of 300 (a) How much of the particle remains after 60 years? (b) What is the half-life of the particle? (a) 4=300e-0.0045 A = 300e-0.064360) A = 300 e-0 0045 60) A=300e-0.27 1 = 229 mg 300 2 0045 = 150 = 0.5 In e-0.0045 = In 0.5A colony of bacteria grows according to the law N = Noe". At the start of a certain experiment there was 144 bacteria present. Eight hours later it was observed that the colony has grown to 720. What was the size of the population 6 hours after the start of the experiment? When 1 =0 N = 144ek When t - 8 720 - 144ek(8) 720 = 14484 5 - git In5 - Ine In5 - 8k k = = = 0.2012 8 When t - 6 N - 48110. The half-life of a certain radioactive substance is 16 days. An initial amount of 30 grams is obtained for a medical treatment. What is the amount of the substance after 9 days? [Use N = Noel] N = 30ek When t = 16 30ek(16)- 15 N = 30g-0.043321 61 1. Evaluate the following logarithm without the use of a calculator. (a) log 10 (b) Inve (c) 1000 loss (d) e 2last 12. Use the properties of logarithm to express as sum or difference Ve (a) In (b) In a - In ve - Inxle" In In12. Use the properties of logarithm to express as sum or difference ( a ) in ve (b) In a 2 + 2 - In ve -Inxe2* In 2 1 2 1 - -[ In(at -x7)- In(a' + =]) ] 4-21x - 2x -In(a - x) + - In(a + x) -=In(a' +=3)13. Use the fact that In 2 = 0.6931, In 3 = 1 0986, and In 5 = 1.6094 to estimate In V7.2 In v72 - b( 7.2) -= ( 7.2) 36 = In 36 In In[ In 36 - In 5] 0.987014. If in x = t and In y = u, write the following in terms of t and u. In In re Inxe' - ly+In x -1+2 -u17. Evaluate the following logarithm without the use of a calculator (a) log v1000 (b) In east (c) 25 2 1 18. Use the change of bases formula to estimate the value of log , 17 to four decimal places log 219. If log x - a , log y = b and log = = c. write log-/10xy= in terms of a,b, and c. log ,/10xy= = log( 10m=) 4 log 10xy=20. Show that (log , 7)(log , 3)(log , 50)) - 2 +log, 2 (log s 7)(log - 3)(log , 50))_ log\\7 . log 3 log 50 log 5 log 7 log 3 log 50 log 5 - 2 + logs2

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