I tried this question so many times. But, I cannot solve the problem for sure.

I would like to get explanation or have an equation that I can solve the problem.

I always got wrong answers. Please provide me what is right answer.

I really don't understand and I'm stuck on it.

1. Let x be a random variable that represents the weights in kilograms (kg) of healthy adult female deer (does) in December in a national park. Then x has a distribution that is approximately normal with mean = 69.0 kg and standard deviation = 8.1 kg. Suppose a doe that weighs less than 60 kg is considered undernourished.

Q. If the park has about 2350 does, what number do you expect to be undernourished in December? (Round your answer to the nearest whole number.)

-> ( ? ) does

Q.To estimate the health of the December doe population, park rangers use the rule that the average weight of n = 45 does should be more than 66 kg. If the average weight is less than 66 kg, it is thought that the entire population of does might be undernourished. What is the probability that the average weight x

for a random sample of 45 does is less than 66 kg (assuming a healthy population)? (Round your answer to four decimal places.)

Q.Compute the probability that x

<70.3 kg for 45 does (assume a healthy population). (Round your answer to four decimal places.)

1. Allen's hummingbird has been studied by zoologist Bill Alther. Suppose a small group of 10 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with = 0.34 gram.

Q. Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.)

-> ( ? ) lower limit

-> ( ? ) upper limit

Q. Find the sample size necessary for an 80% confidence level with a maximal margin of error E = 0.14 for the mean weights of the hummingbirds. (Round up to the nearest whole number.)

-> ( ? ) hummingbirds

1. Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma. Over a period of months, an adult male patient has taken ten blood tests for uric acid. The mean concentration was x = 5.35 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with = 1.91 mg/dl.

Q.Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. (Round your answers to two decimal places.)

-> (? ) lower limit

-> (? ) upper limit

Q.Find the sample size necessary for a 95% confidence level with maximal margin of error E = 1.20 for the mean concentration of uric acid in this patient's blood. (Round your answer up to the nearest whole number.)

-> ( ?) blood tests

1. What price do farmers get for their watermelon crops? In the third week of July, a random sample of 45 farming regions gave a sample mean of x = $6.88 per 100 pounds of watermelon. Assume that is known to be $1.90 per 100 pounds.

Q.Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their watermelon crop. (Round your answers to two decimal places.)

lower limit $ ( ?)

upper limit $ (?)

Q.Find the sample size necessary for a 90% confidence level with maximal error of estimate E = 0.43 for the mean price per 100 pounds of watermelon. (Round up to the nearest whole number.)

( ? ) farming regions

Q. A farm brings 15 tons of watermelon to market. Find a 90% confidence interval for the population mean cash value of this crop. What is the margin of error? Hint: 1 ton is 2000 pounds. (Round your answers to two decimal places.)

lower limit $ ( ?)

upper limit $ (? )

margin of error $ ( ?)