I understand how this is supposed to work, but I can't figure out how swapping values would expand a character vector, like in section 3 and 5 or how replicating v[3] and v[4] would result in an 8 bit character vector such as in section 4.

1) Store the following binary number as a character string s: 110011.

2) Convert this into a character vector v.

3) Expand the character vector v to 8 bits as follows: swap v[3] and v[4] .

4) Replicate v[3] and v[4] . The result (call it ev) should be a character vector of size 8.

5) Write a function called expand() that takes a binary vector of size 6 as input and returns a binary vector of size 8 as output.

6) Create two character vectors S11 and S12 such that S11 contains the binary representations of the numbers (5,2,1,6,3,4,7,0), and S12 contains those of the numbers (1,4,6,2,0,7,5,3).

7) Let b=1101. Extract the last three characters. Convert the last three characters into decimal and store it in a variable called tempVal. Write an if-then-else statement such that if b[1] == 0 retrieve the value of S11[tempval]. If b[1]==1 retrieve the value of S12[tempval] and store it in a variable tempRet. (Hint: You might need to shift the indices by 1)

8) Write a function called S11_function that takes a block of 4-character binary (such as 1110) and, using the two s-boxes from question 6, returns a 3-character binary number using the logic that if the first character is 0 then use S11, otherwise use S12.