Question: ided Practice Given the function r(x) = 2(1+0.35)-* e Work: (1+0.35)-* f(t) = p(1+r)* Exponent Initial Value Rate of + Growth Decay (time) Percent
ided Practice Given the function r(x) = 2(1+0.35)-* e Work: (1+0.35)-* f(t) = p(1+r)* Exponent Initial Value Rate of + Growth Decay (time) Percent rate of change: What does a negative exponent mean? Is the function increasing or decreasing. The percent rate of change is The function is an example of exponential
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