Identify $an$ antiderivative $we$ can use $to$ evaluate the indefinite integral

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{sin6t}{cos3t}dt.$

$sin(3t)+C$

$-\frac{2}{3}cos(3t)+C$

$-\frac{1}{2}sin(2t)+C$

$tan(2t)+C$