Question: If a ball is thrown vertically upward with an initial velocity of96ft/s, then its height after t seconds is s =96 t 16 t 2

If a ball is thrown vertically upward with an initial velocity of96ft/s, then its height aftertseconds iss=96t16t². (Consider up to be the positive direction.)

PLEASE HELP WITH THE FOLLOWING:

1) What is the maximum height (in ft) reached by the ball?

2) What is the velocity (in ft/s) of the ball when it is128ft above the ground on its way up?

3) What is the velocity (in ft/s) of the ball when it is128ft above the ground on its way down?

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