Question: If a cis a, b = cis. beta and c = cis. gama , prove that ab/c + c / ab = 2 cos

If a cis a, b = cis. beta and c = cis.

If a cis a, b = cis. beta and c = cis. gama , prove that ab/c + c / ab = 2 cos (alpha + Beta - gama) y) a 1 b c = 2 cos (pa + q + ry).

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