If A it is bijective: find u such that AU = - N . If A is surjective but not injective: find u such that AU = A where u does not equal - If A is injective but not surjective: find u such that its first two elements are 1 and u is in the image of A. In otherwords: U = - and v = Ax for some N vector x. Essentially, in this case you must solve for z. Note: For this problem A will always be injective, surjective, or bijective (a) A = ( 2 ? ? ) : I A= np. array ([ [1, 2, 3 ] , [2, 1, 1]]) V= None #YOUR CODE HERE # YOUR CODE HERE v = np . array ( (3, ) ) raise NotImplementedError( )In In In In In [1: = = = [1: H #hidden tests for probLem 1.5(a) are within this ceLL 2