If $a_n=\frac{3^n}{9^{n+1}},$ then:

a$.r=\frac{a_{n+1}}{a_n}=$

b$.\underset{n}{lim}{a}_n=$ and

c$.{\displaystyle \underset{n=0}{\overset{}{}}}{a}_n=$

If $b_n=\frac{9}{10},$ then:

a$.r=\frac{b_{n+1}}{b_n}=$

b$.\underset{n}{lim}{b}_n=$ and

c$.{\displaystyle \underset{n=0}{\overset{}{}}}{b}_n=$

If $c_n=(\frac{2}{3}{)}^{5+2n},$ then:

a$.r=\frac{c_{n+1}}{c_n}=$

b$.\underset{n}{lim}{c}_n=$ and

c$.{\displaystyle \underset{n=0}{\overset{}{}}}{c}_n=$

If $d_n=(-10{)}^{4-n},$ then:

a$.r=\frac{d_{n+1}}{d_n}=$

b$.\underset{n}{lim}{d}_n=$ iill, and

c$.{\displaystyle \underset{n=0}{\overset{}{}}}{d}_n=$