Question: If ( a>0 ) and ( b>0 ), then ( sqrt{frac{16 a}{b^{3}}}= ) none of these ( 4 a b^{-2 / 3} ) ( 4

If \$ a>0 \$ and \$ b>0 \$, then \$ \\sqrt{\\frac{16 a}{b^{3}}}= \$ none of these \$ 4 a b^{-2 / 3} \$ \$ 4 a^{1 / 2} b^{-3 / 2} \$ \$ 16 a^{1 / 2} b^{-3 / 2} \$ \$ 16 a b^{-2 / 3} \$

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