Question: If an object with mass m is dropped from rest, one model for its speed v after t seconds, taking air resistance into account, is

If an object with mass m is dropped from rest, one model for its speed v after t seconds, taking air resistance into account, is
v =
mgc
(1 ectm),
where g is the acceleration due to gravity and c is a positive constant. (Note that the air resistance is proportional to the velocity of the object; c is the proportionality constant.)
(a)
Calculate
limtv.
0
What is the meaning of this limit in the context of this problem?
It is the speed the object approaches as time goes on.It is the time it takes for the object to stop.It is the time it takes the object to reach its maximum speed.It is the speed the object reaches before it starts to slow down.
(b)
For fixed t, use l'Hospital's Rule to calculate
limc0+v.
0
What can you conclude about the velocity of a falling object in a vacuum?
An object falling in a vacuum will accelerate at a slower rate than an object not in a vacuum.The heavier the object is the faster it will fall in a vacuum.The velocity of a falling object is proportional to its mass in a vacuum.The velocity of a falling object in a vacuum is directly proportional to the amount of time it falls.

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