If f$($x$)=3$x$^2-3$x$+5,$ find f$(-3).$

f$(-3)=$

Use this to find the equation of the tangent line to the parabola y$=3$x$2-3$x$+5$ at the point $(-3,41).$ The equation of this tangent line can be written in the form y$=$mx$+$b

where m is: $$

and where b is:

$$