Question: If f(a) = f'(a)= 0 and g' y(x) = f(x) g(x) y(x) = f'(x) g'(x) y(x) =. * constant, then the solution of f[g(x)-g(t)]y(t)dt

If f(a) = f'(a)= 0 and g' y(x) = f(x) g(x) y(x)

If f(a) = f'(a)= 0 and g' y(x) = f(x) g(x) y(x) = f'(x) g'(x) y(x) =. * constant, then the solution of f[g(x)-g(t)]y(t)dt = f (x) is d f(x)] dx g(x) y(x) = f'(x) dx g'(x)]

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