Question: If find the confidence interval confidance level se = 32 512=28 S2 11 dd = 5 = 40 11 92%. = 41 n = 100

If

confidance level se = 32 512=28 S2 11 dd = 5 = find the confidence interval

confidance level se = 32 512=28 S2 11 dd = 5 = 40 11 92%. = 41 n = 100 12=200

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