Question: If In(x2 - 3y) = x - y + 3 and y(-2) = 1, find y'(-2) by implicit differentiation. y'(-2) = An equation of the

If In(x2 - 3y) = x - y + 3 and

If In(x2 - 3y) = x - y + 3 and y(-2) = 1, find y'(-2) by implicit differentiation. y'(-2) = An equation of the tangent line to the curve at the point ( - 2, 1) is y

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