if it is correct, I will upvote.

Find a minimum cost implementation of the following function: f(x, X2, X3) = TTM(0, 4, 5, 6, 7) In this situation, cost is defined as the number of logic gates (ANDS, ORs, and NOTs), plus the number of gate inputs. However, complementing the inputs (!x,, !xy, and !xz) is a zero-cost operation, meaning do not count the NOT gate and its input for !x,, !X2, and !Xz. For example, the cost of !x4+x, is 3, 1 OR gate plus 2 inputs, !x, and xz. Hint 1: You could start by finding the canonical SOP or POS (whichever is better for this situation), and then, if necessary, use Boolean algebra to simplify further Hint 2: Your final solution should have a cost of 6