Question: If := q 2 p 3 > 0, let r be the real cube roots of the real numbers q . Show that r+ +
If := q 2 p 3 > 0, let r be the real cube roots of the real numbers q . Show that r+ + r is a real solution of the cubic equation x^3 - 3px - 2q = 0, whereas r+ + 2 r and 2 r+ + r form a complex-conjugate pair of solutions
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