If the above data segments overlap $($in the time domain$)$ by $50\%$ of their length, this results in $9(6\mathrm{.}4$ second long each$)$ segments instead of $5.$ What is the resulting: F minimum $=$ Hz $($integer$)$ Hz $($integer$)$ Will the frequency resolution improve due to overlapping the data segments? $($Type $0$ for No$,1$ for Yes$)$ If the variance of the original $($i$.$e$.,$unsegmented$)$ data is P$2$xx$,$ what is new expected variance after dividing the data in overlapping segments? Answer: New variance $=$ p$2$xx$/($integer$)$