Question: If the calculate ( int x , int y ) method is overridden by a subclass, how can the superclass implementation of the method be

If the calculate(int x, int y) method is overridden by a subclass, how can the
superclass implementation of the method be called from the subclass with x =1, y =
2?
a) super(calculate(1,2));
b) calculate(1,2);
c) super.calculate(1,2);
d) superclass.calculate(1,2);

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