If torque at $A=30MNm($anticlockwise$),$ torque at $C$ is $25MNm($clockwise$)$ and the angle of twist at $E,\frac{O}{{?}_E}$ is $625$rad, the angle of twist at $G$ will be Take JG$=3\mathrm{.}1{?}^{**}{10}^{10}Nm{m}^2$

Power at $F=2000$ MW angular velocitv. $w=200ra\frac{d}{s}$

A

D

El

a$.(250+\frac{5**{10}^3**2000}{{3\mathrm{.}1}^{**}{10}^{10}})$

b$.(250+\frac{5**{10}^9**2000}{{3\mathrm{.}1}^{**}{10}^{10}})$

c$.(250+\frac{5**{10}^6**1000}{{3\mathrm{.}1}^{**}{10}^{10}})$

d$.(250+\frac{5**{10}^6**2000}{{3\mathrm{.}1}^{**}{10}^{10}})$