Question: If x 0 = x 0 , x k = x k 1 + v k , k = 1 , , K , is

If x0=x0, xk=xk1+vk, k=1,,K , is it possible touse Bayes' rule to factor p(x0,x1,,xKx0,v1,,vk) in the following way:p(x0,x1,,xKx0,v1,,vK)=p(x0x0)k=1Kp(xkxk1,vk)?

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