Question: If X has a hypergeometric distribution with M = 3, N = 6 and n = 2, find the probability distribution of Y, the number

If X has a hypergeometric distribution with M = 3, N = 6 and n = 2, find the probability

distribution of Y, the number of successes minus the number of failures

a) h(0) = 1/5 , h(1) = 3/5 , h(2) = 1/5

b) h(0) = 2/5 , h(1) = 3/8 , h(2) = 1/5

c) h(0) = 9/5 , h(1) = 3/5 , h(2) = 1/5

d) h(0) = 1/5 , h(1) = 4/5 , h(2) = 1/5

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