If you estimate

$S={\displaystyle \underset{n=1}{\overset{}{}}}\frac{(-1{)}^{n1}}{n^{3}1}$

with

$\frac{1}{2}-\frac{1}{9}\frac{1}{28}-\frac{1}{65}\frac{1}{126}-\frac{1}{217}=0\mathrm{.}4125467$dots

what is an estimate of the error involved?

Select one:

a$.\frac{1}{344}$

b$.\frac{1}{217}$

c$.\frac{1}{126}$

d$.\frac{1}{6}$