If you look at the answer key for C$...$ it says that you interpolate data from a$-9$E but I am pretty sure that is the refrigerant $22.$ Am I not understanding something here?PROBLEM $3\mathrm{.}11($CONTINUED$)$

$($c$)$ Ammonia at $p=200lb\frac{f}{i}{n}^2,T=195F.$ Find $v,$ in $f\frac{t^3}{l}b.$

$T$

Since $T>T_{\text{s}\text{a}\text{t}},$ the state is in the superheated vapor

region. Interpolating in Table A$-9$E:

$v=0\mathrm{.}3497+$

$\frac{195-180}{(200-180{)}^{*}}(0\mathrm{.}3661-0\mathrm{.}3497)$

$=0\mathrm{.}3620f\frac{t^3}{l}$blongleftrightarrow

$[$PROBLEM $3\mathrm{.}11$

For each case, determine the specific volume at the indicated state. Locate the state on a sketch

of the T$-$v diagram.

$($a$)$ Water at p $=1$ bar, T $=20$oC$.$ Find v$,$ in m$3$

$/$kg$.$

$($b$)$ Refrigerant$-22$ at p $=40$ lbf$/$in$\mathrm{.}2$

$,$ x $=0\mathrm{.}6.$ Find v$,$ in ft$3$

$/$lb$.$

$($c$)$ Ammonia at p $=200$ lbf$/$in$\mathrm{.}2$

$,$ T $=195$o

F$.$ Find v$,$ in ft$3$

$/$lb$.]$