If $z$ is defined implicity as a differentiable function of $x$ and $y$ by the equation $xyz=sin(3x-2y-z),$ then $\frac{\text{d}\text{e}\text{l}\text{z}}{\text{d}\text{e}\text{l}\text{x}}=$

a$.\frac{3cos(3x-2y-z)+xy}{cos(3x-2y-z)-yz}$

b$.\frac{cos(3x-2y-z)+yz}{3cos(3x-2y-z)-xy}$

c$.\frac{3sin(3x-2y-z)-yz}{sin(3x-2y-z)+xy}$

d$.\frac{3yz-cos(3x-2y-z)}{xy+cos(3x-2y-z)}$

$\frac{3cos(3x-2y-z)-yz}{cos(3x-2y-z)+xy}$