Question: If3x2-y2=36, show that ds2=12y2(x2-3)dx2.The function sis the arc length function for y=f(x). What is the differential of arc length?A.ds=1+(dydx)2dx2B.ds=1+(dydx)22dxC.ds=[1+(dydx)2]dxD.ds=1+dydx2dxFind dydx.Todo this, first solve the given

If3x2-y2=36, show that ds2=12y2(x2-3)dx2.The function sis the arc length function for y=f(x). What is the differential of arc length?A.ds=1+(dydx)2dx2B.ds=1+(dydx)22dxC.ds=[1+(dydx)2]dxD.ds=1+dydx2dxFind dydx.Todo this, first solve the given equation for y.y=Differentiate yto find dydx.dydx=3x3x2-362Substitute dydx into the equation for ds and simplify, writing the radicand as a single term.ds=()dx

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