Question: (ii) For an input signal x[n] , the moving-average y[n] for 3 samples is: y[n]=(1)/(3)(x[n-1]+x[n]+x[n+1]) The moving average for k samples, where k is
(ii) For an input signal
x[n], the moving-average
y[n]for 3 samples is:\
y[n]=(1)/(3)(x[n-1]+x[n]+x[n+1])\ The moving average for
ksamples, where
kis an odd integer, is:\
y[n]=(1)/(k)\\\\sum_(i=-(k-1)/(2))^(i=(k-1)/(2)) x[n-i].\ In this scenario,
x[n]is Bitcoin price vs. work week and
y[n]is a filtered output signal. On the same plot as part (i), plot the 7-week moving average and 15-week moving average.
![(ii) For an input signal x[n], the moving-average y[n] for 3](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2024/09/66f4613081a6c_69666f46130251cf.jpg)
(ii) For an input signal x[n], the moving-average y[n] for 3 samples is: y[n]=31(x[n1]+x[n]+x[n+1]) The moving average for k samples, where k is an odd integer, is: y[n]=k1i=(k1)/2i=(k1)/2x[ni]. In this scenario, x[n] is Bitcoin price vs. work week and y[n] is a filtered output signal. On the same plot as part (i), plot the 7 -week moving average and 15 -week moving average
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