Question: (ii) For an input signal x[n] , the moving-average y[n] for 3 samples is: y[n]=(1)/(3)(x[n-1]+x[n]+x[n+1]) The moving average for k samples, where k is

(ii) For an input signal

x[n]

, the moving-average

y[n]

for 3 samples is:\

y[n]=(1)/(3)(x[n-1]+x[n]+x[n+1])

\ The moving average for

k

samples, where

k

is an odd integer, is:\

y[n]=(1)/(k)\\\\sum_(i=-(k-1)/(2))^(i=(k-1)/(2)) x[n-i].

\ In this scenario,

x[n]

is Bitcoin price vs. work week and

y[n]

is a filtered output signal. On the same plot as part (i), plot the 7-week moving average and 15-week moving average.

 (ii) For an input signal x[n], the moving-average y[n] for 3

(ii) For an input signal x[n], the moving-average y[n] for 3 samples is: y[n]=31(x[n1]+x[n]+x[n+1]) The moving average for k samples, where k is an odd integer, is: y[n]=k1i=(k1)/2i=(k1)/2x[ni]. In this scenario, x[n] is Bitcoin price vs. work week and y[n] is a filtered output signal. On the same plot as part (i), plot the 7 -week moving average and 15 -week moving average

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