Question: I'm getting this wrong repeatedly too. Please help. I'm taking 56, the probability that both pedestrian and driver are intoxicated and dividing that with 986=

I'm getting this wrong repeatedly too. Please help.

I'm taking 56, the probability that both pedestrian and driver are intoxicated and dividing that with 986= 0.05679513. Or 5.67. This is wrong.

The table summarizes results from 986 pedestrian deaths that were caused by automobile accidents.

Driver Intoxicated? Pedestrian Intoxicated?
Yes No
Yes 56 79
No 229 622

If one of the pedestrian deaths is randomly selected, find the probability that both the pedestrian and the driver were intoxicated. Report the answer as a percent rounded to one decimal place accuracy.

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