Question: I'm posting this question 2nd time. Because first time fake tutor answer totally wrong and irrelevant. kindly give me true solution as required Question 7:

 I'm posting this question 2nd time. Because first time fake tutor

I'm posting this question 2nd time. Because first time fake tutor answer totally wrong and irrelevant. kindly give me true solution as required

Question 7: Let n > 2 be an integer, and let Ali...n] be an array storing n pairwise distinct numbers. It is easy to compute the two smallest numbers in the array A: Using n-1 comparisons, we find the smallest number in A. Then, using n - 2 comparisons, we find the smallest number among the remaining n - 1 numbers. The total number of comparisons made is 2n - 3. By a similar argument, we can find the smallest and largest numbers in A using 2n -- 3 comparisons. In this question, you will show that the number of comparisons can be improved (7.1) Consider the following algorithm TwoSMALLEST(A,n), which computes the two smallest numbers in the array A: = Algorithm TWOSMALLEST(A.n): if A[1]

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