Question: I'm trying to write a Java function that takes a singly linked list : a->b->a->b->a->b->a->null, and groups both even and odd nodes based on position

I'm trying to write a Java function that takes a singly linked list: a->b->a->b->a->b->a->null, and groups both even and odd nodes based on position (not value). The function should work in-place and return all even nodes first, followed by odd nodes: b->b->b->a->a->a->a->null. I currently have the following solution:

I'm trying to write a Java function that takes a singly linked

However, this produces the error: Cannot assign field "next" because "even" is null. Could you please help fix this? The funtion must make all even nodes first, followed by all odd nodes.

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