Question: Imagine being an attacker. You found a message encrypted using the algorithm RSA. The public key (N,e) is equal to (187, 107). The ciphertext C

Imagine being an attacker. You found a message encrypted using the algorithm RSA. The public key (N,e) is equal to (187, 107). The ciphertext C is 2.

You notice that the N value is not very large... maybe you would be able to factor it and crack the ciphertext. What is the plaintext P?

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