Question: Imagine you are a developer on the Exxen engineering team. You are tasked with enhancing the user experience by implementing a feature that efficiently calculates
Imagine you are a developer on the Exxen engineering team. You are tasked with
enhancing the user experience by implementing a feature that efficiently calculates the median
age of Exxen users. This feature will be crucial for tailoring content recommendations based on
user age demographics.
Exxen, the largest video streaming platform in Turkey, offers a vast array of movies, TV
shows, documentaries, and more. As the user base expands, so does the need for improved
content recommendation systems. A significant part of this improvement is understanding the
median age of users, which helps in creating targeted content suggestions.
As part of a demographic study, Exxen is interested in the median age of its viewers. You
are responsible for implementing functionality that updates the median age efficiently whenever
a new user signs up To achieve this efficiently, you will use two heaps priority queues in Java:
a maxheap to store the smaller half of the ages and a minheap to store the larger half of the
ages. When a new age is added, if the age is less than or equal to the root of the maxheap, it is
added to the maxheap. Otherwise, it is added to the minheap. After each insertion, you balance
the heaps.
If the maxheap has more than one extra element compared to the minheap, you move
the root of the maxheap to the minheap. If the minheap has more elements than the maxheap,
you move the root of the minheap to the maxheap. To find the median, if the heaps are of equal
size, the median is the average of the roots of both heaps. If the heaps are not of equal size, the
median is the root of the maxheap. This method ensures efficient insertion and median retrieval,
suitable for the dynamic and growing user base of Exxen.
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