Implement a function in assembly that would do the following:

$-$Loop through a sequence of characters in a string and swap them such that the end result is the original string in reverse $(50$ points $)$

$-$Before looping, call another assembly function$/$segment to extract the number of characters in the string $(30$ points $)$

$-$For swapping characters, call another assembly function$/$segment to do just that $(20$ points $)$

C$++$ Code:

#include

using namespace std;

extern"C$"\{$

void reverse$($char$[])$;

int length$($char$[])$;

$\}$

int main$()$

$\{$

char myString$[]=$ "abcde";

int x $=0$;

cout $<<$ "Length: $"<<$ length$($myString$)<<$ endl;

cout $<<$ "Original: $"<<$ myString $<<$ endl;

reverse$($myString$)$;

cout $<<$ "Reversed: $"<<$ myString $<<$ endl;

system$("$pause$")$;

return $0$;

$\}$

Reverse Assembly:

$\mathrm{.}686$

$.$model flat

$.$code

$\_$reverse PROC

push ebp

mov ebp,esp ;stack pointer to ebp

mov ebx,$[$ebp$+8]$ ; address of first array element

mov al$,[$ebx$]$

mov ah$,[$ebx$+1]$

mov cl$,$ al ;

mov al$,$ ah

mov ah$,$ cl

mov $[$ebx$],$ al

mov $[$ebx$+1],$ ah

pop ebp

ret

$\_$reverse ENDP

END

Length Assembly:

$\mathrm{.}686$

$.$model flat

$.$code

$\_$length PROC

push ebp

mov ebp,esp

mov ebx,$[$ebp$+8]$

mov eax, $0$

xor dl$,$ dl

loopAgain:

cmp $[$ebx$+$eax$],$ dl

je allDone

add eax, $1$

jmp loopAgain

allDone:

pop ebp

ret

$\_$length ENDP

END