Implement the below logic function with an $8$:$1$ multiplexer and an inverter. $(2$p$)$

$\frac{?}{\text{b}\text{a}\text{r}}\frac{(A{)}_3}{b}ar(A{)}_2\frac{A_1}{b}ar(A{)}_0\frac{+}{b}ar\frac{(A{)}_3}{b}ar(A{)}_2{A}_1{A}_0\frac{+}{b}ar(A_3)A_2\frac{A_1}{b}ar(A{)}_0\frac{+}{b}ar(A{)}_3{A}_2{A}_1{A}_0+\frac{A_3}{b}ar\frac{(A{)}_2}{b}ar\frac{(A{)}_1}{b}ar(A{)}_0+\frac{A_3}{b}ar(A{)}_2\frac{A_1}{b}ar(A_0)+\frac{A_3}{b}ar(A{)}_2{A}_1{A}_0+$

$A_3\frac{A_2}{b}ar(A{)}_1{A}_0+A_3{A}_2{A}_1{A}_0$