Question: Implement the boolean function f=(a+~b+c)*b using only NOT and 2-input NAND gates By using Demorgan's LAW I can get: f=(~a*~b)+(~c*~b) Just by looking at the

Implement the boolean function f=(a+~b+c)*b using only NOT and 2-input NAND gates

By using Demorgan's LAW I can get: f=(~a*~b)+(~c*~b)

Just by looking at the expresion and drawing out the cirucuit i know that I can simplify it to: f=(a+c)*b

but im not too sure how to do this with boolean algebra, also is f=(a+c)*b the best reduction

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