Implement the getNodeAtPosition function of the LinkedList class.

Node * LinkedList::getNodeAtPosition(int position)

The job of this function is to return a pointer to the node the node at the given position. If the list is empty, position <= 0 or position > length, then the function should return the null pointer.

This is a helper function that can be used by various other member functions (e.g. insertAtPosition, removeAtPosition, getValue. setValue).

This is what I have so far, but it is wrong

Node * LinkedList::getNodeAtPosition(int position){ if(headPtr == NULL || position <= 0 || position > length) return NULL;

Node *temp = headPtr; for(int i=1; i

return temp; }