Question: Implementing a homebrew malloc (without using malloc!) in the C language. Allocates a block of memory given a size (in bytes), returning a pointer to

Implementing a homebrew malloc (without using malloc!) in the C language. Allocates a block of memory given a size (in bytes), returning a pointer to the beginning of the block you just created. The content of the newly allocated block of memory is not initialized.

Parameter a is the size of the block in bytes

Return a pointer to the block of memory you allocated with this function.

void *malloc(size_t a) { // implement malloc! }

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