import java.util.Scanner;

public class NthRootFinder { public static void main(String[] args) { Scanner sc = new Scanner(System.in); // Read n (for taking the nth root) int n = Integer.parseInt(sc.nextLine()); // Read number to take the nth root of int number = Integer.parseInt(sc.nextLine()); // Read the desired precision int precision = Integer.parseInt(sc.nextLine()); // Print the answer System.out.println(findNthRoot(number, n, precision)); } private static String findNthRoot(int number, int n, int precision) { int lower=0; int upper=number; while (lower

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(10 points) In this problem, we will implement an nth root finder. Re- call that the nth root of z, written "Vx, is the number when raised to the power n gives x. In particular, please fill in the findNthRoot (int number, int n, int precision) method in the class NthRootFinder. The method should return a string representing the nth root of number, rounded to the nearest precision decimal places. If your answer is exact you should fill in the answer with decimal places (i.e. with input 41 and precision 5, we should return 41.00000.) You may not use any library functions for this question In this question, the class NthRootFinder expects 3 lines, where the first line is n (the degree of root to take), the second line is a number, and the third number represents the precision. The output is a single line contain- ing the answer followed by a newline. For example, the following input would generate the output 20.000: 2 400 Additionally, the following input would generate the output 6.86: 2 47 2