In a BOD test, 5 mL of wastewater (DO = 0.0) is mixed with 295 mL of diluting water (DO = 9.0 mg/L). After 5 days' incubation of the mixture, DO = 5.2 mg/L. What is the BOD5 of the wastewater? Assume that all the oxygen used represents the oxygen demand of the wastewater.

 

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Volume of waste water Vw 5 mL Volume of diluting water V 295 mL I... View the full answer