In a computer instruction format, the instruction length is 10 bits and the size of an address field is 3 bits. The system architect has already designed FIFTEEN 2-address instructions and SEVEN 1-address instructions. How many 0-address instruction still possible to accommodate for the instruction set architecture?

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Instruction Format Example 2 Five 2-address instructions You are designing an instruction set for vour computer. 11 Bits Opcode 3 bits Operand 1 Operand 2 4 bits Allthe instructions are of same size (11 bits long). The size of an address field is 4 bits No. Of bits in Opcode -3; then No. Of combinational states - 8, starting from 010 (0002) You have already designed five 2-address instructions and instructions. 710 (1112 from 010 (0002)410 (100) will take to the next group of instructions As we have 5 instruction here, then we will take 40 1-address Then, 3 numbers from 510 (1012) 740 (1112) left, and How many 0-address instructions can still vou can Iit? Justily your answer. 5 101 6 110 ascend CAREER& TECHRUCAL EDUCATION Instruction Format (Cont..) 40 1-address instructions You are designing an instruction set for vour computer. 11 Bits Opcode 7 bits Operand 4 bits All the instructions are of same size (11 bits long) The size of an address field is 4 bits No. Of bits in Opcode7; 3 of them did bring from previous group as below, then 4 are unknown, and the combinational state for each will be 16 51 101 | 101 XXXXXXXX | 24=16 You have already designed five 2-address instructions and instructions 6 | 110 | 110 XXXX XXXX | 24-16 110 0000 XXXX 110 1111 XXXX 40 1-address 7 111 111 0000 XXXX 111 0111 XXXX Here will take 8 instructions only from 0-7,as we taken from first 2 groups (16+16) and 8 from here 40 How many 0-address instructions can still vou can fit? Justify your answer. Then 8 numbers from 810 (10002) ~1510 (11112) left, and will take to the next group of instructions ascend CAREER& TECHRUCAL EDUCATION Instruction Format (Cont.. You are designing an instruction set for vour computer. U-address instruction 11 Bits Opcode No. Of bits in Opcode - 11. We did bring 8 numbers All the instructions are of same size (11 bits long) The size of an address field is 4 bits. from 810 (10002) -1510 (11112) from previous group So, no. Of instruction128 1000 111 1000 xxXX 24 -16 24 = 16 21 16 24 16 24 16 111 1000 0000111 1000 1111 1001 111 1001 xxXX You have already designed five 2-address instructions and instructions 10 1010 111 1010 xxXX 111 1010 0000111 1010 1111 40 1-address11 111 1011 xxXX 12 1100 111 1100 0000111 1100 1111 instructions can still vou can fit? Justify your answer. 24 16 15 21 16 ascend CAREER& TECHRUCAL EDUCATION