In a dental x-ray tube, electrons are released (at rest), and then are pushed thru a...

 

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In a dental x-ray tube, electrons are released (at rest), and then are pushed thru a 0.15 m vertical distance by a uniform Electric field_ typically 6.0E5 [N/C](t, upward), . (a. calculate an electron's acceleration in this field ... me=0.911E-30[kg], so you can probably ignore gravity :-)) b. use answer (a) to obtain the electron's speed after the push ends. O 714 m/s O 1.05 x 1016 m/s 126 x 106 m/s 1.58 x 1016 m/s 230 × 10³ m/s x O 1010 m/s 593 x 103 m/s 178. x 106 m/s 1.58 x 1016 m/s In a dental x-ray tube, electrons are released (at rest), and then are pushed thru a 0.15 m vertical distance by a uniform Electric field_ typically 6.0E5 [N/C](t, upward), . (a. calculate an electron's acceleration in this field ... me=0.911E-30[kg], so you can probably ignore gravity :-)) b. use answer (a) to obtain the electron's speed after the push ends. O 714 m/s O 1.05 x 1016 m/s 126 x 106 m/s 1.58 x 1016 m/s 230 × 10³ m/s x O 1010 m/s 593 x 103 m/s 178. x 106 m/s 1.58 x 1016 m/s

Answer rating: 100% (QA)

To solve part a of this question we need to calculate the electrons acceleration in an electric field We can do this using Newtons second law Fma wher... View the full answer