in a Packed tower units NOC; and minimum B. A gas mees between these two are mass transfer operations. Explain the banic is subjected mire containing 2.0 mass transfer operations. outlet concentrationter-current absorof solute A at the inlet (and the rest inery) flow rate is 2.0kg/m2 the gas is to be 0.1 mole water in a packed tower. kg/m2sec(MW=18mm2sec(MW=29) and the inlet pure water flow rate is 2.7 equilibrium condition can be described by Henry's Law as: where y and x are the mole fraction of solute A in the vapor and liquid respectively. i. Determine the minimum liquid rate (Lmin) (in kg/m2sec) required for the separation. ii. Determine the number of transfer units (NOG) required for the separation. NOG=(yy)LMy1y2(yy)LM=ln[y2y1y1y](y1y1)(y2y) iii. The column uses a certain type of packings which provides an overall gasphase mass transfer coefficient (KYa) of 0.06kg-mole /(m3-sec-mole fraction). Determine the height of packings (Z) required for the separation. HOG=Kya(1y)iMG(1y)LM=ln[1y11y1](1y1)(1y1)Z=(HOG)(NOG) iv. Determine the actual liquid rate (Lact) (in kg/m2.sec ) assuming the water flow is 1.2 times the minimum. GLmin=x1x2y1y2,GLact=(1.2)Lmin