Question: In a queueing system, customers arrive once every 7 hours (standard deviation ( =5 ) ) and services take 6 hours (standard deviation ( =

In a queueing system, customers arrive once every 7 hours (standard deviation $ =5 $ ) and services take 6 hours (standard deviation $ = $ 5.7). (Do not round intermediate calculations. Round your $deviation $ =5 $ ) and services take 6 hours (standard deviation$

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