In a turbulent boundary layer over a flat plate it is found that $\frac{u}{U}=(\frac{y}{}{)}^{\frac{1}{7}}$ and $C_f=0\mathrm{.}02R{e}_{}^{-\frac{1}{6}}.$ By using Karman momentum integral equation obtain expressions $($i$)$ for $$ and $C_f$ in terms of $R{e}_x,$ and

$($ii$)$ for $C_{Df}$ in terms of $R{e}_L$

$[$:$R{e}_L=U\frac{L}{v}\}$

Ans. $[$:$C_f=\frac{0\mathrm{.}027}{R{e}_x^{\frac{1}{6}}},C_{Df}=\frac{0\mathrm{.}031}{R{e}_L^{\frac{1}{6}}},\frac{}{x}=\frac{0\mathrm{.}16}{R{e}_x^{\frac{1}{7}}}\}$