Question: In a worst - case design scenario, a 2 0 0 0 kg elevator with broken cables is falling at 4 . 0 0 m

In a "worst-case" design scenario, a 2000 kg elevator with broken cables is falling at 4.00 m/s when it first contacts a cushioning spring at the bottom of the shaft. The spring is supposed to stop the elevator, compressing 2.00 m as it does so. Spring coefficient is 10.6 kN/m. During the motion a safety clamp applies a constant 17000-N frictional force to the elevator. What is the speed of the elevator after it has moved downward 1.00 m from the point where it first contacts a spring?

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