In an experiment, you dissolve 0.30 g of KHP (MM = 204.22 g/mol) in 20 mL of
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Question:
In an experiment, you dissolve 0.30 g of KHP (MM = 204.22 g/mol) in 20 mL of DI water and titrate the sample with 0.10 M NaOH. Calculate the volume (to the nearest mL) of NaOH required to reach the equivalence point.
a) 3 ml
b) 15 ml
c) 20 ml
d) 30 ml
e) 100 ml
Expert Answer:
the volume of NaOH required to reach the equivalence point is approximately 147 mL Heres how we can calculate it Calculate the moles of KHP Molar mass ... View the full answer
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