Question: In an unsorted linked list, delete duplicate nodes by traversing the list only once. Add a method removeDuplicates() to the class LinkedList, see the next

In an unsorted linked list, delete duplicate nodes by traversing the list only once. Add a method removeDuplicates() to the class LinkedList, see the next page. The code of the class LinkedList is provided. Test your method from the main. Constraints. For full credit, your solution must meet the following restrictions. A violating solution will be penalized accordingly. A) 20 points if violated. Your code must run in no worse than O(n), where n is the length of the linked list. B) 30 points if violated. Do not leak memory; if you remove nodes from the list, free their associated memory. C) 10 points if violated. Your code must solve the problem by making only a single traversal over the list, not multiple passes. Suggested realization of the LinkedList class. public class LinkedList { private Node head; private class Node { private int value; private Node next; public Node(int value) { } } @Override public String toString() { Node current = head; this.value = value; 1 } StringBuffer toPrint = new StringBuffer(); toPrint.append("["); while (current != null) { if (current.next != null) { toPrint.append(current.value + ", "); } else { toPrint.append(current.value); current = current.next; toPrint.append("]"); return toPrint.toString(); } public void addFirst(int value) { Node node = new Node(value); if (head == null) { head = node; } else { node.next = head; } } } Pls explain and give a brief answer so i check double check and understand

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