In C:

Assume an array has been declared as

float arr$[20][8]$;

What value of $m$ can be used so the following is true?

$($float$*)$arr $+m==$&$(arr[12][2])$

$($i$.$e$.,$ arr $[12][2]$ is $m$ floats ahead of arr in memory$)$

Note: you will lose $10\%$ for each incorrect submission.

Answer:

Your Submission

Rating

Sub$-$Subject

Topic

C Programming Language

Passing Arrays To Functions

Step$-$by$-$step

Step $1$ of $3$

To find the value of $m$ in$,$

$1(float)arr+m==$&$(arr[12][2]),$

we need to understand the memory layout of a $2$D array.

In C$,$ a $2$D array is stored in a contiguous block of memory. The address of arr$[0][0]$ is the same as the address of arr$[0][1]+$sizeof$(float),$ Rows? $v?$ neea to skip $1$ rows $($Irom inaex $$ to $|{)}_1),$ and each row is $8$ floats. So$,12**8=96$ floats.

Columns: We need to skip $2$ columns $($from index $0$ to $1)$ in the $12$th row, which is an additional $2$ floats.

So$,m=96+2=98.$

Explanation:

Therefore, the correct answer is $m=98.$