In C language:

In this exercise you will split string based on another string. For example "String to be split", which is split by " ", will result in an array containing the split parts: ["String","to","be","split",NULL]. The resulting arrays will always end with a NULL pointer.

The exercise has two parts:

1. Implement a function void print_split_string(char** split_string), which prints a split string, each part on its own line. For example when calling the function for a split string ["String","to","be","split",NULL], the function prints:

 String to be split

2. Implement functions

   • char** split_string(const char* str, const char* split)

     The function splits a string in the aforementioned way and returns the parts in a dynamically reserved array. Parameters are as follows:

     • const char* str, the string to be split
     • const char* split, the string used to split str, for example "One. .more. .test. .for. .string. .splitting." and ". .", when the result is an array consisting of the following pieces: ["One","more","test","for","string","splitting.",NULL]

     Also, the pieces need to have their memory dynamically reserved and they need to be copied to the array. The function strstr may be helpful in this exercise.

   • free_split_string(char** split_string)

     The function frees the memory for the split string array.

The main.c looks like this:

#include #include #include "stringsplit.h"

int main() { char str1[] = "Test string split with this test string"; char str2[] = "Another - test - for - string - split";

char** str1_split = split_string(str1, " "); char** str2_split = split_string(str2, " - "); printf("\"%s\" split: ", str1); print_split_string(str1_split);

printf(" \"%s\" split: ", str2); print_split_string(str2_split); free_split_string(str1_split); free_split_string(str2_split);

return 0; }