Question: in c++, only solution code pls and thank u Define a private helper function called ConvertToFahrenheit() that converts the data member celsius to Fahrenheit and

in c++, only solution code pls and thank u

Define a private helper function called ConvertToFahrenheit() that converts the data member celsius to Fahrenheit and returns a double.

Ex: If the input is 138.0, then the output is:

280.4 degrees Fahrenheit 

Note: The equation to convert from Celsius to Fahrenheit is: fahrenheit = (celsius * 1.8) + 32

#include #include #include using namespace std; class Today { public: void SetCelsius(double todayCelsius); double GetCelsius() const; void PrintInFahrenheit(); private: double celsius; double ConvertToFahrenheit(); }; void Today::SetCelsius(double todayCelsius) { celsius = todayCelsius; } double Today::GetCelsius() const { return celsius; } /* Your code goes here */ void Today::PrintInFahrenheit() { cout << fixed << setprecision(1) << ConvertToFahrenheit() << " degrees Fahrenheit" << endl; } int main() { Today today1; double inputCelsius; cin >> inputCelsius; today1.SetCelsius(inputCelsius); today1.PrintInFahrenheit(); return 0; }

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